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二分法变种

时间:2016-05-12 17:05:36      阅读:133      评论:0      收藏:0      [点我收藏+]

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package com

public class Test {
    public static void main(String[] args) {
        int[] nums = {4,7,7,9,12,13};
        int index = searchLastSmaller(nums,1);
        System.out.println(index);
    }
    
    /*
     * 第一个与key相等的元素
     */
    public static int searchFirstEqual(int[] arr, int key){
        int left = 0, right = arr.length-1;
        while(left<=right){
            int mid = (left+right)/2;
            if(arr[mid]>=key)right=mid-1;
            else if(arr[mid]<key) left = mid+1;
        }
        if(left<arr.length&&arr[left]==key) return left;
        return -1;
    }
    
    /*
     * 找出最后一个与key相等的元素
     */
    public static int searchLastEqual(int[] arr, int key){
        int left = 0, right = arr.length-1;
        while(left<=right) {
            int mid = (left+right)/2;
            if(arr[mid] > key) right = mid - 1;
            else if(arr[mid] <= key) left = mid + 1; 
        }
        if( right>=0 && arr[right] == key) return right;
        return -1;
    }
    
    /*
     * 找出第一个大于等于key的元素
     * 
     */
    
    public static int searchFirstEqualOrLarger(int arr[],int key){
        int left=0, right=arr.length-1;
        while(left<=right) {
            int mid = (left+right)/2;
            if(arr[mid] >= key) right = mid-1;
            else if (arr[mid] < key) left = mid+1;
        }
        if(left>=arr.length)return -1;
        return left;
    }
    
    /*
     * 查找第一个大于key的元素
     */
    public static int searchFirstLarger(int[] arr, int key){
        int left=0, right=arr.length-1;
        while(left<=right) {
            int mid = (left+right)/2;
            if(arr[mid] > key) right = mid-1;
            else if (arr[mid] <= key) left = mid+1;
        }
        if(left>=arr.length)return -1;
        return left;
    }
    
    /*
     * 查找最后一个小于或等于Key的元素
     */
    public static int searchLastEqualOrSmaller(int[] arr, int key){
        int left=0, right=arr.length-1;
        while(left<=right) {
            int m = (left+right)/2;
            if(arr[m] > key) right = m-1;
            else if (arr[m] <= key) left = m+1;
        }
        //若right=-1,表明不存在
        return right;
    }
    
    /*
     * 查找最后一个小于key的元素
     */
    public static int searchLastSmaller(int[] arr, int key){
        int left=0, right=arr.length-1;
        while(left<=right) {
            int mid = (left+right)/2;
            if(arr[mid] >= key) right = mid-1;
            else if (arr[mid] < key) left = mid+1;
        }
        //若right=-1,表明不存在
        return right;
    }

}

二分法变种

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原文地址:http://blog.csdn.net/u013238950/article/details/51361138

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