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1,0 2,1 4,2,0 1,2,0 1 10,6,4,2,1 0 0
1,0,1 1,1,1,0 1,0,0,0,0,0
细心点 把,分割的数字读取出来就行了
#include <stdio.h>
#include <string.h>
#include <stack>
#include <math.h>
using namespace std;
int main()
{
	char num1[1000];
	char num2[1000];
	int prim[26]={0,2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97};
	while(~scanf("%s %s",num1,num2))
	{
		if(strcmp(num1,"0")==0&&strcmp(num2,"0")==0)
		break; 
		int len1=strlen(num1);
		int len2=strlen(num2);
		int t1=len1-1,t2=len2-1;
		stack<int>s;
		int r=0;
		int cnt=1;
		while(t1>=0||t2>=0)
		{
			int mul=0;
			int a=0,b=0;
			for(;t1>=0;t1--)
			{
				if(num1[t1]>='0'&&num1[t1]<='9')
				a=a+(num1[t1]-'0')*pow(10,mul++);
				else
				break;
			}
			mul=0;
			for(;t2>=0;t2--)
			{
				if(num2[t2]>='0'&&num2[t2]<='9')
				b=b+(num2[t2]-'0')*pow(10,mul++);
				else
				break;
			}
	
			
		//	printf("r=%d \n",a+b+r);
			s.push((a+b+r)%prim[cnt]);
			r=(a+b+r)/prim[cnt];
			t1--,t2--,cnt++;
		}
		if(r)
		s.push(r);
		printf("%d",s.top());s.pop();
		while(!s.empty())
		printf(",%d",s.top()),s.pop();
		printf("\n");
	}
} 
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原文地址:http://blog.csdn.net/su20145104009/article/details/51336876