Leetcode--Two Sum

标签：des   style   blog   color   os   io   for   2014   

Problem Description:

Given an array of integers, find two numbers such that they add up to a specific target number.

The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.

You may assume that each input would have exactly one solution.

Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2

    
   struct node{
        int val;
        int indexs;
    };  

    bool compare(node a,node b)
    {
        return a.val<b.val;
    }    

class Solution {
public:

    vector<int> twoSum(vector<int> &numbers, int target) {
        vector<int> res;
        if(numbers.size()<2) 
            return res;
        vector<node> nums;
        for(vector<int>::size_type index=0;index!=numbers.size();++index)
        {
            node temp;
            temp.val=numbers[index];
            temp.indexs=index+1;
            nums.push_back(temp);
        }
        
        sort(nums.begin(),nums.end(),compare);
        
        vector<node>::iterator p=nums.begin();
        vector<node>::iterator q=nums.end()-1;
        while(p<q)
        {
            if((p->val+q->val)>target)
                q--;
            else 
            if((p->val+q->val)<target)
                p++;
            else
            {
                if(p->indexs<q->indexs)
                {
                    res.push_back(p->indexs);
                    res.push_back(q->indexs);
                }
                else
                {
                    res.push_back(q->indexs);
                    res.push_back(p->indexs);
                }
                break;
            }
        }
        return res;
    }
};

class Solution {
public:
    vector<int> twoSum(vector<int> &numbers, int target) {
        vector<int> res;
        if(numbers.size()<2)
            return res;
        unordered_map<int,int> numsmap;
        
        for(vector<int>::size_type index=0;index!=numbers.size();++index)
            numsmap[numbers[index]]=index;
        unordered_map<int,int>::iterator flag=numsmap.end();
        
        for(vector<int>::size_type index=0;index!=numbers.size();++index)
        {
            int temp=target-numbers[index];
            flag=numsmap.find(temp);
            if(flag!=numsmap.end()&&flag->second!=index)
            {
                if(index<flag->second)
                {
                    res.push_back(index+1);
                    res.push_back(flag->second+1);
                }
                else
                {
                    res.push_back(flag->second+1);
                    res.push_back(index+1);
                }
                break;
            }
        }
        return res;
    }
};

Leetcode--Two Sum,布布扣,bubuko.com

Leetcode--Two Sum

标签：des   style   blog   color   os   io   for   2014   

原文地址：http://blog.csdn.net/longhopefor/article/details/38322565