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Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
算法思路:
求出各个子树是否是平衡二叉树。为了防止多余计算,最好采取后序遍历。
代码如下:
1 public class Solution { 2 public boolean isBalanced(TreeNode root) { 3 if(root == null || (root.left == null && root.right == null)) 4 return true; 5 if(!isBalanced(root.left) || !isBalanced(root.right)) 6 return false; 7 int left = getHeight(root.left); 8 int right = getHeight(root.right); 9 if(Math.abs(right - left) > 1) return false; 10 return true; 11 } 12 13 private int getHeight(TreeNode root){ 14 if(root == null) return 0; 15 if(root.left == null && root.right == null) return 1; 16 int left = 0,right = 0; 17 if(root.left != null) left = getHeight(root.left); 18 if(root.right != null) right = getHeight(root.right); 19 return Math.max(left, right) + 1; 20 } 21 }
[leetcode]Balanced Binary Tree,布布扣,bubuko.com
[leetcode]Balanced Binary Tree
标签:style blog http color io for ar 代码
原文地址:http://www.cnblogs.com/huntfor/p/3883531.html