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[leetcode]Balanced Binary Tree

时间:2014-07-31 23:20:20      阅读:267      评论:0      收藏:0      [点我收藏+]

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Balanced Binary Tree

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

算法思路:

求出各个子树是否是平衡二叉树。为了防止多余计算,最好采取后序遍历。

代码如下:

 1 public class Solution {
 2    public boolean isBalanced(TreeNode root) {
 3         if(root == null || (root.left == null && root.right == null))
 4             return true;
 5         if(!isBalanced(root.left) || !isBalanced(root.right))
 6             return false;
 7         int left = getHeight(root.left);
 8         int right = getHeight(root.right);
 9         if(Math.abs(right - left) > 1) return false;
10         return true;
11     }
12     
13     private int getHeight(TreeNode root){
14         if(root == null) return 0;
15         if(root.left == null && root.right == null) return 1;
16         int left = 0,right = 0;
17         if(root.left != null) left = getHeight(root.left);
18         if(root.right != null) right = getHeight(root.right);
19         return Math.max(left, right) + 1;
20     }
21 }

 

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[leetcode]Balanced Binary Tree

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原文地址:http://www.cnblogs.com/huntfor/p/3883531.html

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