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hdu 2818 Building Block

时间:2016-05-14 12:37:35      阅读:125      评论:0      收藏:0      [点我收藏+]

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Building Block

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4558    Accepted Submission(s): 1415

Problem Description
John are playing with blocks. There are N blocks (1 <= N <= 30000) numbered 1...N。Initially, there are N piles, and each pile contains one block. Then John do some operations P times (1 <= P <= 1000000). There are two kinds of operation:
M X Y : Put the whole pile containing block X up to the pile containing Y. If X and Y are in the same pile, just ignore this command. C X : Count the number of blocks under block X
You are request to find out the output for each C operation.
 
Input
The first line contains integer P. Then P lines follow, each of which contain an operation describe above.
 
Output
Output the count for each C operations in one line.
 
Sample Input
6
M 1 6
C 1
M 2 4
M 2 6
C 3
C 4
 
Sample Output
1
0
2

hdu 2818 Building Block

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原文地址:http://www.cnblogs.com/qinduanyinghua/p/5492194.html

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