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递归建树,然后BFS一下
#include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<queue> #include<vector> using namespace std; const int maxn=40; int a[maxn],b[maxn]; int n,tot; struct Node { int left; int right; int val; }node[maxn]; void build(int L,int R,int fa,int f) { int P=-1; for(int i=L;i<=R;i++) for(int j=1;j<=n;j++) if(b[i]==a[j]) P=max(P,j); int root_val=a[P]; if(tot==0) { ++tot; node[tot].val=root_val; } else if(f==0) { ++tot; node[tot].val=root_val; node[fa].left=tot; } else if(f==1) { ++tot; node[tot].val=root_val; node[fa].right=tot; } int tmp=tot; for(int i=L;i<=R;i++) { if(b[i]==root_val) { if(i-L>0) build(L,i-1,tmp,0); if(R-i>0) build(i+1,R,tmp,1); break; } } } void bfs() { queue<int>Q; Q.push(1); int cnt=0; while(!Q.empty()) { int head=Q.front(); Q.pop(); printf("%d",node[head].val); cnt++; if(cnt<n) printf(" "); else printf("\n"); if(node[head].left!=-1) Q.push(node[head].left); if(node[head].right!=-1) Q.push(node[head].right); } } int main() { scanf("%d",&n); tot=0; for(int i=1;i<=n;i++) scanf("%d",&a[i]); for(int i=1;i<=n;i++) scanf("%d",&b[i]); for(int i=0;i<=30;i++) node[i].left=node[i].right=-1; build(1,n,-1,-1); bfs(); return 0; }
PAT (Advanced Level) 1020. Tree Traversals (25)
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原文地址:http://www.cnblogs.com/zufezzt/p/5499430.html