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剑指offer第五题:从尾到头打印链表:利用栈的‘后进先出’/递归
1 //============================================================================ 2 // Name : JZ-C-05.cpp 3 // Author : Laughing_Lz 4 // Version : 5 // Copyright : All Right Reserved 6 // Description : Hello World in C++, Ansi-style 7 //============================================================================ 8 9 #include <iostream> 10 #include <iomanip> 11 #include <stack> 12 #include <list> 13 using namespace std; 14 15 typedef struct SNode { 16 int data; 17 struct SNode *next; 18 } NODE; 19 20 /*从尾到头打印链表:递归*/ 21 void PrintListReverse1(NODE * head) { 22 if (head != NULL) { 23 if (head->next != NULL) { 24 PrintListReverse1(head->next); //递归 25 } 26 cout << head->data << setw(3); 27 } 28 } 29 /*从尾到头打印链表:利用栈的后进先出特点*/ 30 void PrintListReverse2(NODE *head) { 31 std::stack<NODE*> nodes; //创建一个栈,存入NODE*类型的元素 32 NODE *p = head; 33 while (p != NULL) { 34 nodes.push(p); //压入栈中 35 p = p->next; 36 } 37 while (!nodes.empty()) { 38 cout <<nodes.top()->data << setw(3); //‘后进先出‘出栈 39 nodes.pop(); 40 } 41 } 42 /*建立一个单链表*/ 43 NODE* CreatList() { 44 NODE *node1 = new NODE(); 45 NODE *node2 = new NODE(); 46 NODE *node3 = new NODE(); 47 NODE *node4 = new NODE(); 48 NODE *node5 = new NODE(); 49 node1->data = 1; 50 node2->data = 2; 51 node3->data = 3; 52 node4->data = 4; 53 node5->data = 5; 54 node1->next = node2; 55 node2->next = node3; 56 node3->next = node4; 57 node4->next = node5; 58 node5->next = NULL; 59 return node1; 60 } 61 int main() { 62 NODE *head = CreatList(); 63 // NODE *head = NULL; 64 PrintListReverse2(head); 65 return 0; 66 }
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原文地址:http://www.cnblogs.com/Laughing-Lz/p/5502754.html