码迷,mamicode.com
首页 > 其他好文 > 详细

convert-sorted-list-to-binary-search-tree

时间:2016-05-20 23:48:26      阅读:207      评论:0      收藏:0      [点我收藏+]

标签:

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.

public class Solution {
    public TreeNode sortedListToBST(ListNode head) {
        int len=lenOFlist(head);
         TreeNode root=creatTree(head,0,len-1);
        return root;
        
    }
    public TreeNode creatTree(ListNode head,int left,int right){
        if(left>right)return null;
        int mid=(right+left+1)/2;/// right-(right-left+1)/2
        ListNode p=head;
        for (int i = left; i < mid; i++) {
            p=p.next;
        }
        TreeNode node=new TreeNode(p.val);
        TreeNode leftTree=creatTree(head, left, mid-1);
        TreeNode rightTree=creatTree(p.next, mid+1, right);
        node.left=leftTree;
        node.right=rightTree;
        
        return node;
        
    }
    public int lenOFlist(ListNode head){
        ListNode p=head;
        int count = 0;
        while(p!=null){
            count++;
            p=p.next;
        }
        return count;
    }
    
}

 

convert-sorted-list-to-binary-search-tree

标签:

原文地址:http://www.cnblogs.com/softwarewebdesign/p/5513721.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!