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LeetCode:Intersection of Two Arrays

时间:2016-05-22 12:12:52      阅读:162      评论:0      收藏:0      [点我收藏+]

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Intersection of Two Arrays




Total Accepted: 5682 Total Submissions: 12479 Difficulty: Easy

Given two arrays, write a function to compute their intersection.

Example:
Given nums1 = [1, 2, 2, 1]nums2 = [2, 2], return [2].

Note:

  • Each element in the result must be unique.
  • The result can be in any order.

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java code:

public class Solution {
    public int[] intersection(int[] nums1, int[] nums2) {
        
        int len1 = nums1.length,len2 = nums2.length;
        
        Set<Integer> set = new HashSet<Integer>();
        Set<Integer> interSet = new HashSet<Integer>();
        
        for(int i=0;i<len1;i++) {
            set.add(nums1[i]);
        }
        
        for(int i=0;i<len2;i++) {
            if(set.contains(nums2[i])) interSet.add(nums2[i]);
        }
        
        int[] ret = new int[interSet.size()];
        int cnt = 0;
        for(int num:interSet) {
            ret[cnt++] = num;
        }
        
        return ret;
        
    }
}


LeetCode:Intersection of Two Arrays

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原文地址:http://blog.csdn.net/itismelzp/article/details/51474024

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