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简单题。
#include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<vector> using namespace std; const int maxn=100000; struct X { string name; string sex; string id; int c; }s[maxn]; int n; int main() { scanf("%d",&n); for(int i=1;i<=n;i++) cin>>s[i].name>>s[i].sex>>s[i].id>>s[i].c; int id1=-1,id2=-1; int Max=-1,Min=99999; for(int i=1;i<=n;i++) if(s[i].sex[0]==‘F‘&&s[i].c>Max) Max=s[i].c,id1=i; for(int i=1;i<=n;i++) if(s[i].sex[0]==‘M‘&&s[i].c<Min) Min=s[i].c,id2=i; if(id1==-1) printf("Absent\n"); else cout<<s[id1].name<<" "<<s[id1].id<<endl; if(id2==-1) printf("Absent\n"); else cout<<s[id2].name<<" "<<s[id2].id<<endl; if(id1==-1||id2==-1) printf("NA\n"); else printf("%d\n",abs(s[id1].c-s[id2].c)); return 0; }
PAT (Advanced Level) 1036. Boys vs Girls (25)
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原文地址:http://www.cnblogs.com/zufezzt/p/5519545.html