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Given a binary tree, return the inorder traversal of its nodes‘ values.
For example:
Given binary tree {1,#,2,3}
,
1 2 / 3
return [1,3,2]
.
代码如下:
1 /** 2 * Definition for a binary tree node. 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 public List<Integer> inorderTraversal(TreeNode root) { 12 List<Integer> list=new ArrayList<>(); 13 14 if(root==null) 15 return list; 16 17 if(root.left!=null) 18 list.addAll(inorderTraversal(root.left)); 19 list.add(root.val); 20 if(root.right!=null) 21 list.addAll(inorderTraversal(root.right)); 22 23 return list; 24 } 25 }
94. Binary Tree Inorder Traversal
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原文地址:http://www.cnblogs.com/ghuosaao/p/5523728.html