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Given a binary tree
struct TreeLinkNode {
TreeLinkNode *left;
TreeLinkNode *right;
TreeLinkNode *next;
}
Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL.
Initially, all next pointers are set to NULL.
Note:
For example,
Given the following perfect binary tree,
1
/ 2 3
/ \ / 4 5 6 7
After calling your function, the tree should look like:
1 -> NULL
/ 2 -> 3 -> NULL
/ \ / 4->5->6->7 -> NULL
代码如下：
1 /** 2 * Definition for binary tree with next pointer. 3 * public class TreeLinkNode { 4 * int val; 5 * TreeLinkNode left, right, next; 6 * TreeLinkNode(int x) { val = x; } 7 * } 8 */ 9 public class Solution { 10 public void connect(TreeLinkNode root) { 11 int a=1; 12 int b=a; 13 List<TreeLinkNode> list=LevelTraverse(root); 14 15 try{ 16 int i=0; 17 while(i<list.size()) 18 { 19 TreeLinkNode node=list.get(i); 20 i++; 21 b=b-1; 22 while(b>0) 23 { 24 node.next=list.get(i); 25 i++; 26 node=node.next; 27 b--; 28 } 29 node.next=null; 30 b=a*2; 31 a=b; 32 } 33 }catch(NullPointerException e){} 34 35 } 36 public ArrayList<TreeLinkNode> LevelTraverse(TreeLinkNode root)//树的水平遍历 37 { 38 ArrayList<TreeLinkNode> list=new ArrayList<TreeLinkNode>(); 39 Queue<TreeLinkNode> queue = new LinkedList<TreeLinkNode>(); 40 queue.add(root); 41 try{ 42 while(queue.size()>0) 43 { 44 TreeLinkNode a=(TreeLinkNode)queue.peek(); 45 queue.remove(); 46 list.add(a); 47 if(a.left!=null) 48 queue.add(a.left); 49 if(a.right!=null) 50 queue.add(a.right); 51 } 52 }catch(NullPointerException e){} 53 54 return list; 55 } 56 }
116. Populating Next Right Pointers in Each Node
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原文地址：http://www.cnblogs.com/ghuosaao/p/5524569.html
