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时间:2016-05-26 06:18:34      阅读:248      评论:0      收藏:0      [点我收藏+]

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create table <表名>
(
    <列名> <数据类型及长度> [not null],
    <列名> <数据类型及长度>,
    ...
    <列名> <数据类型及长度>
)

drop table <表名>


导入导出数据
把表变成sql代码
备份与还原

 

习题  创建表格
技术分享

增,删,改,查  CRUD

添加:
insert into <表名>[(列1,列2....)] values(<‘值1‘>[,‘值2‘])
注意:
1.列与值要匹配(数量,类型,次序)
2.列可以省掉,但值必须与表中的总列数和列的次序完全对应。
3.自增长列,不能省掉自增列,给自增列赋个‘‘




delete from car where code=‘c001‘
delete from car where brand=‘b001‘ or brand=‘b004‘
delete from car where brand=‘b001‘ || brand=‘b004‘
delete from car where brand=‘b007‘ && price>50
delete from car where brand=‘b007‘ and price>50

<>  !=


更新
update <表名> set <列=值>[,列=值...] where .....
update info set sex=‘1‘  where code=‘p003‘
update info set sex=‘0‘,nation=‘n004‘,birthday=‘1999-9-9‘ where code=‘p001‘
update car set price=price * 0.9 where price > 30
update car set price =price * 0.95 where (brand=‘b006‘ || brand=‘b005‘)&&price>30



查询
select * from 表名
select 列名1,列名2... from 表名        --投影
select * from 表名 where 条件        --筛选

1.等值与不等值
select * from car where code=‘c001‘;
select * from car where code != ‘c001‘;
select * from car where price > 30;
--下面的都是范围
select * from car where price >=30 && price <=50;
select * from car where price between 30 and 50
select * from car where brand=‘b002‘ || brand=‘b004‘ || brand=‘b006‘
select * from car where brand in (‘b002‘,‘b004‘,‘b006‘)

2.模糊查
select * from car where name like ‘宝马%‘        %--任意多个任意字符
select * from car where name like ‘%5%‘
select * from car where name like ‘%型‘
select * from car where name like ‘__5%‘        _ -- 一个任意字符

3.排序
select * from 表名 where .... order by 列名 [ASC/DESC],列名[asc/desc]....

select * from car order by  price desc
select * from car order by brand desc,price asc
习题
技术分享

Navicat

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原文地址:http://www.cnblogs.com/zoubizhici/p/5529483.html

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