【Leetcode】Counting Bits

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题目链接：https://leetcode.com/problems/counting-bits/

题目：

Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1‘s in their binary representation and return them as an array.

Example:
For num = 5 you should return [0,1,1,2,1,2].

Follow up:

• It is very easy to come up with a solution with run time O(n*sizeof(integer)). But can you do it in linear time O(n) /possibly in a single pass?
• Space complexity should be O(n).
• Can you do it like a boss? Do it without using any builtin function like __builtin_popcount in c++ or in any other language.

算法：

public int[] countBits(int num) {  
    int res[] = new int[num+1];  
    for(int i=0;i<=num;i++){  
        res[i] = res[i>>1]+(i&1);  
    }  
    return res;  
}  

【Leetcode】Counting Bits

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原文地址：http://blog.csdn.net/yeqiuzs/article/details/51520468