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密码

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 29823    Accepted Submission(s): 11976

#include <stdio.h>
#include <string.h>
int main()
{
    char s[55];
    char ope[]="~!@#$%^\0";
    int f,f1,f2,f3,f4,M,i,j;
    scanf("%d",&M);
    getchar();
    while(M--)
    {
        gets(s);
        f1=f2=f3=f4=f=0;
        if(strlen(s)>=8&&strlen(s)<=16)f=1;
        if(f)
        for(i=0;s[i];i++)
        {
            if(s[i]>=‘a‘&&s[i]<=‘z‘)f1=1;
            if(s[i]>=‘A‘&&s[i]<=‘Z‘)f2=1;
            if(s[i]>=‘0‘&&s[i]<=‘9‘)f3=1;
            for(j=0;ope[j];j++)if(s[i]==ope[j])f4=1;
        }
        if(f1+f2+f3+f4>=3&&f)printf("YES\n");
        else printf("NO\n");
    }
    return 0;
}

View Code

#include <stdio.h>
#include <string.h>
int main()
{
 char s[55];
 char ope[]="~!@#$%^\0";
 int f,f1,f2,f3,f4,M,i,j;
 scanf("%d",&M);
 getchar();
 while(M--)
 {
  gets(s);
  f1=f2=f3=f4=f=0;
  if(strlen(s)>=8&&strlen(s)<=16)f=1;
  if(f)
  for(i=0;s[i];i++)
  {
   if(s[i]>=‘a‘&&s[i]<=‘z‘)f1=1;
   if(s[i]>=‘A‘&&s[i]<=‘Z‘)f2=1;
   if(s[i]>=‘0‘&&s[i]<=‘9‘)f3=1;
   for(j=0;ope[j];j++)if(s[i]==ope[j])f4=1;
  }
  if(f1+f2+f3+f4>=3&&f)printf("YES\n");
  else printf("NO\n");
 }
 return 0;
}

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hdu 2043密码

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原文地址：http://www.cnblogs.com/2014acm/p/3887131.html