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Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals.
For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be:
[1, 1] [1, 1], [3, 3] [1, 1], [3, 3], [7, 7] [1, 3], [7, 7] [1, 3], [6, 7]
Follow up:
What if there are lots of merges and the number of disjoint intervals are small compared to the data stream‘s size?
Credits:
Special thanks to @yunhong for adding this problem and creating most of the test cases.
这道题说有个数据流每次提供一个数字，然后让我们组成一系列分离的区间，这道题跟之前那道Insert Interval很像，思路也很像，每进来一个新的数字val，我们都生成一个新的区间[val, val]，然后将其插入到当前的区间里，注意分情况讨论，无重叠，相邻，和有重叠分开讨论处理，参见代码如下:
class SummaryRanges { public: /** Initialize your data structure here. */ SummaryRanges() {} void addNum(int val) { Interval cur(val, val); vector<Interval> res; int pos = 0; for (auto a : v) { if (cur.end + 1 < a.start) { res.push_back(a); } else if (cur.start > a.end + 1) { res.push_back(a); ++pos; } else if (cur.start - 1 == a.end) { cur.start = a.start; } else if (cur.end + 1 == a.start) { cur.end = a.end; } else { cur.start = min(cur.start, a.start); cur.end = max(cur.end, a.end); } } res.insert(res.begin() + pos, cur); v = res; } vector<Interval> getIntervals() { return v; } private: vector<Interval> v; };
类似题目：
参考资料:
https://leetcode.com/discuss/105742/simple-java-solution-using-insert-interval
LeetCode All in One 题目讲解汇总(持续更新中...)
[LeetCode] Data Stream as Disjoint Intervals 分离区间的数据流
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原文地址：http://www.cnblogs.com/grandyang/p/5548284.html
