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LeetCode-Valid Anagram

时间:2016-06-01 06:48:51      阅读:115      评论:0      收藏:0      [点我收藏+]

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Given two strings s and t, write a function to determine if t is an anagram of s.

For example,
s = "anagram", t = "nagaram", return true.
s = "rat", t = "car", return false.

Note:
You may assume the string contains only lowercase alphabets.
public class Solution {
    public boolean isAnagram(String s, String t) {
        if(s.length() != t.length()){
            return false;
        }
        HashMap<Character, Integer> map=new HashMap<Character, Integer>();
        for(int i=0; i<s.length(); i++){
            char c=s.charAt(i);
            if(map.containsKey(c)){
                int count=map.get(c)+1;
                map.put(c, count);
            }
            else{
                map.put(c,1);
            }
        }
        for(int i=0; i<t.length(); i++){
            char c=t.charAt(i);
            if(map.containsKey(c)){
                int count=map.get(c)-1;
                map.put(c,count);
            }
            else{
                return false;
            }
        }
        for(Character c : map.keySet()){
            if(map.get(c)!=0){
                return false;
            }
        }
        return true;
        
    }
}

 

LeetCode-Valid Anagram

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原文地址:http://www.cnblogs.com/incrediblechangshuo/p/5548293.html

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