标签:
模拟源码实现:
int isspace(int c)
{
return (c == ' ' || c == '\t' || c == '\n' || c == '\r' || c == '\f' || c == '\v');
}#include <stdio.h>
#include <ctype.h>
main()
{
char str[]="a3 4\t%\r8\n9 [\ve\f?";
int i = 0;
for(i=0;str[i]!=0;i++)
{
if(isspace(str[i]))
{
printf("%c 是空格\n",str[i]);
}
else
{
printf("%c 不是空格\n",str[i]);
}
}
}
运行结果:
标签:
原文地址:http://blog.csdn.net/kongshuai19900505/article/details/51559609