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题意:n个字符串,如果元音就是输出大写,否则输出小写。
析:没啥可说的,只要判断AEIOU就OK了。
代码如下:
#include <iostream> #include <cstdio> #include <algorithm> #include <queue> #include <vector> #include <cstring> #include <map> #include <cctype> using namespace std; const int maxn = 70; char s[maxn]; bool judge(char ch){ if(‘A‘ == towupper(ch) || ‘E‘ == towupper(ch) || ‘I‘ == towupper(ch) || ‘O‘ == towupper(ch) || ‘U‘ == towupper(ch)) return true; return false; } int main(){ int T; scanf("%d", &T); while(T--){ scanf("%s", s); int n = strlen(s); for(int i = 0; i < n; ++i) if(judge(s[i])) printf("%c", towupper(s[i])); else printf("%c", towlower(s[i])); printf("\n"); } return 0; }
HDU 3079 Vowel Counting (水题。。。判断元音)
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原文地址:http://www.cnblogs.com/dwtfukgv/p/5553982.html