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Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive),
prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one.
Note:
O(n2)
.Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.
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思路:
解法类似于找有环的链表中的入口点。
c++ code:
class Solution { public: int findDuplicate(vector<int>& nums) { int size = nums.size(); if(size < 2) return -1; int slow = nums[0]; int fast = nums[nums[0]]; while(slow != fast) { slow = nums[slow]; fast = nums[nums[fast]]; } fast = 0; while(slow != fast) { slow = nums[slow]; fast = nums[fast]; } return slow; } };
LeetCode:Find the Duplicate Number
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原文地址:http://blog.csdn.net/itismelzp/article/details/51569023