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Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 6422 | Accepted: 2202 |
Description
Input
Output
Sample Input
6 4 1 2 3 4 2 3 1 4 4 2 3 1 3 1 2 4 1 3 4 2 1 4 2 3 2 1 3 2
Sample Output
2
Hint
#include <stdio.h> #include <algorithm> #include <queue> #include <string.h> #include <math.h> #include <iostream> #include <math.h> using namespace std; const int N = 1100; const int INF = 999999999; struct Edge{ int v,next; int w; }edge[N*N]; struct Cow{ int love[25]; }cow[N]; int head[N]; int level[N]; int graph[N][N],dis[N][N],cap[N]; int tot; void init(){ memset(head,-1,sizeof(head)); tot=0; } void addEdge(int u,int v,int w,int &k){ edge[k].v = v,edge[k].w=w,edge[k].next=head[u],head[u]=k++; edge[k].v = u,edge[k].w=0,edge[k].next=head[v],head[v]=k++; } int BFS(int src,int des){ queue<int >q; memset(level,0,sizeof(level)); level[src]=1; q.push(src); while(!q.empty()){ int u = q.front(); q.pop(); if(u==des) return 1; for(int k = head[u];k!=-1;k=edge[k].next){ int v = edge[k].v; int w = edge[k].w; if(level[v]==0&&w!=0){ level[v]=level[u]+1; q.push(v); } } } return -1; } int dfs(int u,int des,int increaseRoad){ if(u==des) return increaseRoad; int ret=0; for(int k=head[u];k!=-1;k=edge[k].next){ int v = edge[k].v; int w = edge[k].w; if(level[v]==level[u]+1&&w!=0){ int MIN = min(increaseRoad-ret,w); w = dfs(v,des,MIN); if(w>0){ edge[k].w -=w; edge[k^1].w+=w; ret+=w; if(ret==increaseRoad) return ret; }else level[v] = -1; } } return ret; } int Dinic(int src,int des){ int ans = 0; while(BFS(src,des)!=-1) ans+=dfs(src,des,INF); return ans; } int n,b,src,des; int build(int t,int mid){ init(); for(int i=1;i<=b;i++){ addEdge(src,i,cap[i],tot); } for(int i=1;i<=n;i++){ addEdge(i+b,des,1,tot); } for(int i=t;i<=t+mid-1&&i<=b;i++){ for(int j=1;j<=n;j++){ addEdge(cow[j].love[i],j+b,1,tot); } } return Dinic(src,des); } int main(){ scanf("%d%d",&n,&b); src = 0,des = n+b+1; for(int i=1;i<=n;i++){ for(int j=1;j<=b;j++){ scanf("%d",&cow[i].love[j]); } } for(int i=1;i<=b;i++) scanf("%d",&cap[i]); int l =0,r = b; int ans = b; while(l<=r){ int mid = (l+r)>>1; ///差值 bool flag = false; for(int i=1;i<=b;i++){ ///枚举最小值 if(build(i,mid)==n) { flag = 1; break; } } if(flag) { ans = mid; r = mid-1; }else l = mid+1; } printf("%d\n",ans); }
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原文地址:http://www.cnblogs.com/liyinggang/p/5557376.html