第四次作业

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结对对象：何季生

贡献比例：50%;50%

#include "stdafx.h"
#include<iostream>
#include<fstream>
#include<cstring>
using namespace std;

struct Num{
int num = 1;
char *s = NULL;
};

Num word[99];

int Judge(char danci[])//判断单词
{
bool j1 = (strlen(danci) >= 4);
bool j2 = (danci[0] >= ‘a‘ && danci[0] <= ‘z‘);
if (!(j1&&j2))
return -1;
else
for (int ns = 1; danci[ns] != ‘\0‘;)
{
if (!((danci[ns] >= ‘a‘ && danci[ns] <= ‘z‘) || (danci[ns] >= ‘0‘ && danci[ns] <= ‘9‘)))
return -1;
else
ns++;
}
}
int Sta(char danci[], int nn) //判断该单词是否出现过
{
if (nn>0)
for (int i = 0; i <nn; i++)
{
if (!strcmp(danci, word[i].s)) //出现
{
word[i].num++; //+1
return -1;
}
}
}
int main()
{
char sentence[1000];//字符数组长度要足够大
ifstream file("d://A_Tale_of_Two_Cities.txt");
ofstream outfile("d://Result1.txt"); //读取
if (!file){
cout << "Unable to open file";
exit(1);
}
if (!outfile){
cout << "Unable to open outmyfile";
exit(1);
}
while (!file.eof())
{
file.getline(sentence, 1000);
}
file.close();
int num2 = 0;
while (sentence[num2] != ‘\0‘)//转小写
{
if (sentence[num2] >= ‘A‘&&sentence[num2] <= ‘Z‘)
sentence[num2] = sentence[num2] + 32;
num2++;
}
const char *delim = " ,“”.‘‘‘’!?"; //分隔符
char *p,
*pNext = NULL;
int n = 0, //计数器 n ,t 初始化
t = 0;
p = strtok_s(sentence, delim, &pNext); //strtovk_s函数根据分隔符分隔字符串
while (p)
{
if (Judge(p) != -1)
{
if (Sta(p, n) != -1)
{
word[n].s = p;
n++;
}
}
p = strtok_s(NULL, delim, &pNext);
}

while (word[t].s) //输出统计结果
{
cout<< word[t].s << "：" << word[t].num << ‘\n‘;
outfile<< word[t].s << "：" << word[t].num << ‘\n‘;
t++;
}
outfile.close();
return 0;
}

第四次作业

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原文地址：http://www.cnblogs.com/Vpygamalion/p/5559080.html