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LeetCode:Valid Anagram

时间:2016-06-05 12:39:11      阅读:144      评论:0      收藏:0      [点我收藏+]

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Valid Anagram




Total Accepted: 85434 Total Submissions: 201750 Difficulty: Easy

Given two strings s and t, write a function to determine if t is an anagram of s.

For example,
s = "anagram", t = "nagaram", return true.
s = "rat", t = "car", return false.

Note:
You may assume the string contains only lowercase alphabets.

Follow up:
What if the inputs contain unicode characters? How would you adapt your solution to such case?

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c++ code:

class Solution {
public:
    bool isAnagram(string s, string t) {
        
        if(s.length() != t.length()) return false;
        
        int hash[26] = {0};
        
        for(int i=0;i<s.length();i++) hash[s[i]-'a']++;
        for(int i=0;i<t.length();i++) hash[t[i]-'a']--;
        
        for(int h : hash)
            if(h != 0) return false;
        
        return true;
    }
};


LeetCode:Valid Anagram

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原文地址:http://blog.csdn.net/itismelzp/article/details/51588413

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