运算符专项练习

#include<cstdio>
#include<cstring>
#include<iostream>
#define ref(i,a,b) for(i=a;i<=b;i++)
using namespace std;
int a[22],n,m,t;
char c[22][22];
int main()
{   
    cin>>n>>m>>t;
    scanf("\n");
    while (t-->0){
        int i,j;
        memset(a,0,sizeof(a));
        ref(i,1,n){
            ref(j,1,m){
                cin>>c[i][j];
            }
            scanf("\n");
        }
        int v;
        ref(j,1,m){
            v=1;
            ref(i,1,n){//我是把整个图顺时针转了90度，更好操作
                a[j]+=v*(c[i][j]-48);//二进制转换成十进制状态
                v*=2;
            }
        }
        int ans=0,k,b[21],al=(1<<n)-1;
        ref(a[0],0,al){
            ref(i,0,m) b[i]=a[i];
            ref(i,1,m){
                b[i]=(b[i]^(b[i-1]*2)^(b[i-1]*4)^(b[i-1]/4)^(b[i-1]/2)^b[i-1])&al; //操作当前的状态
                b[i+1]=(b[i+1]^b[i-1])&al;//操作下一状态
            }
            if ((b[m]&al)==0) 
            ans++;
        }
        cout<<ans<<endl;
    }
    return 0;
}
/*http://blog.csdn.net/hzj1054689699/article/details/50571564*/