码迷,mamicode.com
首页 > 其他好文 > 详细

LeetCode:Basic Calculator

时间:2016-06-06 17:06:53      阅读:142      评论:0      收藏:0      [点我收藏+]

标签:

Basic Calculator




Total Accepted: 29148 Total Submissions: 128464 Difficulty: Hard

Implement a basic calculator to evaluate a simple expression string.

The expression string may contain open ( and closing parentheses ), the plus + or minus sign -non-negative integers and empty spaces .

You may assume that the given expression is always valid.

Some examples:

"1 + 1" = 2
" 2-1 + 2 " = 3
"(1+(4+5+2)-3)+(6+8)" = 23

Note: Do not use the eval built-in library function.

Subscribe to see which companies asked this question

Hide Tags
 Stack Math

























java code:

public class Solution {
    public int calculate(String s) {
        
        Stack<Integer> stack = new Stack<Integer>();
        
        int result = 0;
        int sign = 1;
        int n = s.length();
        
        for(int i=0;i<n;i++) {
            
            char c = s.charAt(i);
            if(Character.isDigit(c)) {
                int sum = c-'0';
                while(i+1<n && Character.isDigit(s.charAt(i+1))) {
                    sum = 10*sum + s.charAt(i+1)-'0';
                    i++;
                }
                result += sign * sum;
            } else if(c=='+') {
                sign = 1;
            } else if(c=='-') {
                sign = -1;
            } else if(c=='(') {
                stack.push(result);
                stack.push(sign);
                sign = 1;
                result = 0;
            } else if(c==')') {
                result = result * stack.pop() + stack.pop();
            }
        }
        
        return result;
    }
}


LeetCode:Basic Calculator

标签:

原文地址:http://blog.csdn.net/itismelzp/article/details/51594724

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!