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Decode Ways

时间:2016-06-07 16:06:38      阅读:159      评论:0      收藏:0      [点我收藏+]

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A message containing letters from A-Z is being encoded to numbers using the following mapping:

‘A‘ -> 1
‘B‘ -> 2
...
‘Z‘ -> 26

Given an encoded message containing digits, determine the total number of ways to decode it.

For example,
Given encoded message "12", it could be decoded as "AB" (1 2) or "L" (12).

The number of ways decoding "12" is 2.

 1 class Solution {
 2 public:
 3     int numDecodings(string s) {  
 4       if(s.empty() || s[0] ==0) return 0;
 5       int len=s.length();
 6       if(len==1) return check(s[0]);  
 7       int fn=0, fn1, fn2;
 8       fn1 = check(s[0]);
 9       fn2 = check(s[0], s[1]);       
10       for(int i=1; i< s.size(); i++)  
11       {    
12         if(check(s[i])) fn+= fn1;         
13         if(check(s[i-1], s[i])) fn+=fn2;  
14         if(fn ==0)   
15           return 0;  
16         fn2 = fn1;  
17         fn1 = fn;  
18         fn=0;     
19       }  
20       return fn1;  
21     }  
22     int check(char one)   
23     {  
24       return (one != 0) ? 1 : 0;      
25     }  
26     int check(char one, char two)  
27     {  
28       return (one == 1 || (one == 2 && two <= 6))  
29       ? 1 : 0;      
30     }  
31 };

 

Decode Ways

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原文地址:http://www.cnblogs.com/hexhxy/p/5567263.html

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