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【Leetcode】Length of Last Word

时间:2016-06-12 03:24:44      阅读:191      评论:0      收藏:0      [点我收藏+]

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题目链接:https://leetcode.com/problems/length-of-last-word/

题目:

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.


思路:

easy 不解释

算法:

[java] view plain copy
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  1. public int lengthOfLastWord(String s) {  
  2.     String[] strs = s.split(" ");  
  3.     if (strs.length - 1 >= 0) {  
  4.         return strs[strs.length - 1].length();  
  5.     } else {  
  6.         return 0;  
  7.     }  
  8.   
  9. }  

【Leetcode】Length of Last Word

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原文地址:http://blog.csdn.net/yeqiuzs/article/details/51598059

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