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剑指offer第二十五题:二叉树中和为某一值的路径
1 //============================================================================ 2 // Name : JZ-C-25.cpp 3 // Author : Laughing_Lz 4 // Version : 5 // Copyright : All Right Reserved 6 // Description : 二叉树中和为某一值的路径 7 //============================================================================ 8 9 #include <iostream> 10 #include <stdio.h> 11 #include "BinaryTree.h" 12 #include <vector> 13 14 using namespace std; 15 16 void FindPath(BinaryTreeNode* pRoot, int expectedSum, std::vector<int>& path, 17 int& currentSum); //函数声明 18 19 void FindPath(BinaryTreeNode* pRoot, int expectedSum) { 20 if (pRoot == NULL) { 21 return; 22 } 23 std::vector<int> path; 24 int currentSum = 0; //当前路径值和 25 FindPath(pRoot, expectedSum, path, currentSum); 26 } 27 void FindPath(BinaryTreeNode* pRoot, int expectedSum, std::vector<int>& path, 28 int& currentSum) { 29 currentSum += pRoot->m_nValue; 30 path.push_back(pRoot->m_nValue); 31 // 如果是叶结点,并且路径上结点的和等于输入的值 32 // 打印出这条路径 33 bool isLeaf = pRoot->m_pLeft == NULL && pRoot->m_pRight == NULL; 34 if (isLeaf && currentSum == expectedSum) { 35 printf("A path is found: "); 36 std::vector<int>::iterator it = path.begin(); 37 for (; it != path.end(); it++) { 38 printf("%d\t", *it); 39 } 40 printf("\n"); 41 } 42 // 如果不是叶结点,则遍历它的子结点 43 if (pRoot->m_pLeft != NULL) 44 FindPath(pRoot->m_pLeft, expectedSum, path, currentSum); 45 if (pRoot->m_pRight != NULL) 46 FindPath(pRoot->m_pRight, expectedSum, path, currentSum); 47 48 // 在返回到父结点之前,在路径上删除当前结点, 49 // 并在currentSum中减去当前结点的值 ★★ 50 currentSum -= pRoot->m_nValue; 51 path.pop_back(); 52 53 } 54 // ====================测试代码==================== 55 void Test(char* testName, BinaryTreeNode* pRoot, int expectedSum) { 56 if (testName != NULL) 57 printf("%s begins:\n", testName); 58 59 FindPath(pRoot, expectedSum); 60 61 printf("\n"); 62 } 63 64 // 10 65 // / 66 // 5 12 67 // / 68 // 4 7 69 // 有两条路径上的结点和为22 70 void Test1() { 71 BinaryTreeNode* pNode10 = CreateBinaryTreeNode(10); 72 BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); 73 BinaryTreeNode* pNode12 = CreateBinaryTreeNode(12); 74 BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4); 75 BinaryTreeNode* pNode7 = CreateBinaryTreeNode(7); 76 77 ConnectTreeNodes(pNode10, pNode5, pNode12); 78 ConnectTreeNodes(pNode5, pNode4, pNode7); 79 80 printf("Two paths should be found in Test1.\n"); 81 Test("Test1", pNode10, 22); 82 83 DestroyTree(pNode10); 84 } 85 86 // 10 87 // / 88 // 5 12 89 // / 90 // 4 7 91 // 没有路径上的结点和为15 92 void Test2() { 93 BinaryTreeNode* pNode10 = CreateBinaryTreeNode(10); 94 BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); 95 BinaryTreeNode* pNode12 = CreateBinaryTreeNode(12); 96 BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4); 97 BinaryTreeNode* pNode7 = CreateBinaryTreeNode(7); 98 99 ConnectTreeNodes(pNode10, pNode5, pNode12); 100 ConnectTreeNodes(pNode5, pNode4, pNode7); 101 102 printf("No paths should be found in Test2.\n"); 103 Test("Test2", pNode10, 15); 104 105 DestroyTree(pNode10); 106 } 107 108 // 5 109 // / 110 // 4 111 // / 112 // 3 113 // / 114 // 2 115 // / 116 // 1 117 // 有一条路径上面的结点和为15 118 void Test3() { 119 BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); 120 BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4); 121 BinaryTreeNode* pNode3 = CreateBinaryTreeNode(3); 122 BinaryTreeNode* pNode2 = CreateBinaryTreeNode(2); 123 BinaryTreeNode* pNode1 = CreateBinaryTreeNode(1); 124 125 ConnectTreeNodes(pNode5, pNode4, NULL); 126 ConnectTreeNodes(pNode4, pNode3, NULL); 127 ConnectTreeNodes(pNode3, pNode2, NULL); 128 ConnectTreeNodes(pNode2, pNode1, NULL); 129 130 printf("One path should be found in Test3.\n"); 131 Test("Test3", pNode5, 15); 132 133 DestroyTree(pNode5); 134 } 135 136 // 1 137 // 138 // 2 139 // 140 // 3 141 // 142 // 4 143 // 144 // 5 145 // 没有路径上面的结点和为16 146 void Test4() { 147 BinaryTreeNode* pNode1 = CreateBinaryTreeNode(1); 148 BinaryTreeNode* pNode2 = CreateBinaryTreeNode(2); 149 BinaryTreeNode* pNode3 = CreateBinaryTreeNode(3); 150 BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4); 151 BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); 152 153 ConnectTreeNodes(pNode1, NULL, pNode2); 154 ConnectTreeNodes(pNode2, NULL, pNode3); 155 ConnectTreeNodes(pNode3, NULL, pNode4); 156 ConnectTreeNodes(pNode4, NULL, pNode5); 157 158 printf("No paths should be found in Test4.\n"); 159 Test("Test4", pNode1, 16); 160 161 DestroyTree(pNode1); 162 } 163 164 // 树中只有1个结点 165 void Test5() { 166 BinaryTreeNode* pNode1 = CreateBinaryTreeNode(1); 167 168 printf("One path should be found in Test5.\n"); 169 Test("Test5", pNode1, 1); 170 171 DestroyTree(pNode1); 172 } 173 174 // 树中没有结点 175 void Test6() { 176 printf("No paths should be found in Test6.\n"); 177 Test("Test6", NULL, 0); 178 } 179 180 int main(int argc, char** argv) { 181 Test1(); 182 Test2(); 183 Test3(); 184 Test4(); 185 Test5(); 186 Test6(); 187 188 return 0; 189 }
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原文地址:http://www.cnblogs.com/Laughing-Lz/p/5581146.html