Intersection of Two Arrays II

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Given two arrays, write a function to compute their intersection.

Example:
Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2].

Note:

• Each element in the result should appear as many times as it shows in both arrays.
• The result can be in any order.
• 解题思路：双指针， 排序

   1 public class Solution {
   2     public int[] intersect(int[] nums1, int[] nums2) {
   3         Arrays.sort(nums1);
   4         Arrays.sort(nums2);
   5         int i = 0, j = 0;
   6         int index = 0;
   7         int[] temp = new int[nums1.length];
   8         while (i < nums1.length && j < nums2.length) {
   9             if (nums1[i] == nums2[j]) {
  10                 temp[index++] = nums1[i];
  11                 ++i;
  12                 ++j;
  13             } else if (nums1[i] < nums2[j]) {
  14                 i++;
  15             } else {
  16                 j++;
  17             }
  18         }
  19         int[] result = new int[index];
  20         for (int k = 0; k < index; k++) {
  21             result[k] = temp[k];
  22         }
  23         return result;
  24     }
  25 }

   

Intersection of Two Arrays II

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原文地址：http://www.cnblogs.com/FLAGyuri/p/5582719.html