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Valid Anagram

时间:2016-06-15 15:52:23      阅读:147      评论:0      收藏:0      [点我收藏+]

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Valid Anagram

Given two strings s and t, write a function to determine if t is an anagram of s.

For example,
s = "anagram", t = "nagaram", return true.
s = "rat", t = "car", return false.

Note:
You may assume the string contains only lowercase alphabets.

class Solution {
public:
bool isAnagram(string s, string t) {
vector<int> count(26, 0);
for(int i = 0; i < s.size(); i ++)
count[s[i]-‘a‘] ++;
for(int i = 0; i < t.size(); i ++)
count[t[i]-‘a‘] --;
for(int i = 0; i < 26; i ++)
if(count[i] != 0)
return false;
return true;
}
};
 
 
class Solution {
public:
bool isAnagram(string s, string t) {
sort(s.begin(), s.end());
sort(t.begin(), t.end());
return s == t;
}
};

 

Valid Anagram

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原文地址:http://www.cnblogs.com/dylqt/p/5587380.html

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