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时间:2016-06-15 15:53:25      阅读:105      评论:0      收藏:0      [点我收藏+]

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You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

int climbStairs(int n) {
int step[n];
int i = 0;
if(n <= 2)
return n;
step[0] = 1;
step[1] = 2;
for(i = 2; i < n; i++)
{
step[i] = step[i - 2] + step[i - 1];
}
return step[i - 1];
}
  • 用斐波那契的递归处理,到44时就会消耗过大而失败;
  • 递归在程序最后时,都是可以用for来代替的
  • 在for里面定义的变量,对于for外面也是不可见的!

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原文地址:http://www.cnblogs.com/dylqt/p/5587379.html

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