标签:
Given an unsorted integer array, find the first missing positive integer.
For example,
Given [1,2,0]
return 3
,
and [3,4,-1,1]
return 2
.
Your algorithm should run in O(n) time and uses constant space.
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思路:
将每个数放置到下标对应的位置。
如num=5,将它与nums[4]位置上的数交换;第二次遍历数组,第一个没与位置对应的数即为答案。
java code:
public class Solution { public int firstMissingPositive(int[] nums) { int n = nums.length; for(int i=0;i<n;i++) { while(0 < nums[i] && nums[i] <= n && nums[nums[i]-1] != nums[i]) swap(nums, nums[i]-1,i); } for(int i=0;i<n;i++) { if(nums[i] != i+1) return i+1; } return n+1; } // 自定义函数:交换 private void swap(int[] nums, int i, int j) { nums[i] ^= nums[j]; nums[j] ^= nums[i]; nums[i] ^= nums[j]; } }
LeetCode:First Missing Positive
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原文地址:http://blog.csdn.net/itismelzp/article/details/51685537