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矩阵乘法。
x[n] = {x[0],1} * ( {a,0} ^ n )
{b,1}
写成这样谁能看懂。。。。
noi里的大水题。我居然
#include<cstdio> #include<algorithm> #include<cstring> #include<iostream> #define LL long long using namespace std; const int maxn = 2; LL a,b,mod,g,x,n,ans; LL mul(long long a,long long b) { a%=mod; b%=mod; long long res=0; while(b) { if(b&1) res=(res+a)%mod; a=(a+a)%mod; b>>=1; } return res; } struct Matrix { const static LL n = 1; LL a[maxn][maxn]; inline LL* operator [] (int x) { return a[x]; } Matrix operator* (Matrix b) { Matrix res; for(int i=0;i<=n;i++) for(int j=0;j<=n;j++) for(int k=0;k<=n;k++) res[i][k]=(res[i][k]+mul(a[i][j],b[j][k]))%mod; return res; } void build() { for(int i=0;i<=n;i++) a[i][i]=1; } Matrix operator^ (long long e) { Matrix res,tmp=*this; res.build(); while(e) { if(e&1) res=res*tmp; tmp=tmp*tmp; e>>=1; } return res; } Matrix () { memset(a,0,sizeof(a)); } }res; int main() { cin >> mod >> a >> b >> x >> n >> g; res[0][0]=a; res[1][0]=b; res[1][1]=1; res=res^n; ans=(mul(x,res[0][0])+res[1][0])%mod; ans=ans%g; cout << ans <<‘\n‘; return 0; }
都1A了。
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原文地址:http://www.cnblogs.com/invoid/p/5592104.html