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公式恐惧症患者膜了半天题解QAQ
具体过程见网上其他题解吧>_<
1 #include<cstdio> 2 #include<iostream> 3 #include<cstring> 4 #include<algorithm> 5 #define ll long long 6 #define MOD(x) x-=x>=modd?modd:0 7 using namespace std; 8 const int modd=2333; 9 int c[modd][modd],sum[modd][modd]; 10 ll n,k; 11 12 13 14 inline int lucas(ll a,ll b){ 15 if(a<b)return 0; 16 if(a<modd&&b<modd)return c[a][b]; 17 return c[a%modd][b%modd]*lucas(a/modd,b/modd)%modd; 18 } 19 int calc(ll n,ll k){ 20 if(k<0)return 0; 21 return (calc(n/modd,k/modd-1)*sum[n%modd][2332]+lucas(n/modd,k/modd)*sum[n%modd][k%modd])%modd; 22 } 23 inline void prerun(){ 24 register int i,j; 25 for(i=0;i<modd;i++)c[i][0]=sum[i][0]=sum[0][i]=1; 26 for(i=1;i<modd;i++) 27 for(j=1;j<=i;j++) 28 c[i][j]=c[i-1][j]+c[i-1][j-1],MOD(c[i][j]), 29 sum[i][j]=sum[i][j-1]+c[i][j],MOD(sum[i][j]); 30 for(i=1;i<modd;i++)for(j=i+1;j<modd;j++)sum[i][j]=sum[i][j-1]; 31 } 32 int main(){ 33 prerun();int T; 34 for(scanf("%d",&T);T;T--) 35 scanf("%lld%lld",&n,&k),printf("%d\n",calc(n,k)); 36 } 37
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原文地址:http://www.cnblogs.com/czllgzmzl/p/5596319.html