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UVa 1374 Power Calculus (IDA*或都打表)

时间:2016-06-20 00:38:23      阅读:173      评论:0      收藏:0      [点我收藏+]

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题意:给定一个数n,让你求从1至少要做多少次乘除才可以从 x 得到 xn

析:首先这个是幂级的,次数不会很多,所以可以考虑IDA*算法,这个算法并不难,难在找乐观函数h(x),

这个题乐观函数可以是当前最大数*2maxd - d 小于n,回溯。很好理解,最大的数再一直乘2都达不到,最终肯定达不到。

再就是应该先试乘再试除,还有不要出现负整数。我测了不少知道应该是13次最多,所以这也是一个优化。

为了追求速度,也可以先1~1000的数打表。

代码如下:

#include <iostream>
#include <cstdio>
#include <cstring>
#include <queue>
#include <set>
#include <vector>
#include <algorithm>

using namespace std;
const int maxn = 1000 + 5;
int maxd, n, a[maxn];


bool dfs(int d, int num, int cur){
    if(d == maxd){
        if(n == cur)   return true;
        return false;
    }

    int m = 0;
    for(int i = 0; i < num; ++i) m = max(m, a[i]);
    if(m * (1 << (maxd - d)) < n)  return false;//回溯

    for(int i = num-1; i >= 0; --i){
        a[num] = cur + a[i];   ++num;//乘法
        if(dfs(d+1, num, cur+a[i]))  return true;
        a[num-1] = abs(cur - a[i]);//除法
        if(dfs(d+1, num, abs(cur-a[i])))  return true;
        --num;
    }
    return false;
}

int main(){
    while(scanf("%d", &n) == 1 && n){
        for(maxd = 0; maxd < 13; ++maxd){
            a[0] = 1;
            if(dfs(0, 1, 1)) break;
        }
        printf("%d\n", maxd);
    }
    return 0;
}

 

下面是打表的代码:

#include <iostream>
#include <cstdio>
#include <cstring>
#include <queue>
#include <set>
#include <vector>
#include <algorithm>

using namespace std;

const int ans[]={0,1,2,2,3,3,4,3,4,4,5,4,5,5,5,4,5,5,6,5,6,6,6,5,6,6,6,6,7,6,6,5,6,6,
7,6,7,7,7,6,7,7,7,7,7,7,7,6,7,7,7,7,8,7,8,7,8,8,8,7,8,7,7,6,7,7,8,7,8,8,8,7,8,8,8,8,
8,8,8,7,8,8,8,8,8,8,9,8,9,8,9,8,8,8,8,7,8,8,8,8,9,8,9,8,9,9,9,8,9,9,9,8,9,9,9,9,9,9,9,8,
9,9,9,8,9,8,8,7,8,8,9,8,9,9,9,8,9,9,9,9,9,9,9,8,9,9,9,9,9,9,10,9,9,9,9,9,9,9,9,
8,9,9,9,9,9,9,10,9,10,9,10,9,10,10,10,9,10,10,10,9,10,10,10,9,10,9,10,9,9,9,9,8,
9,9,9,9,10,9,10,9,10,10,10,9,10,10,10,9,10,10,10,10,10,10,10,9,10,10,10,10,10,10,
10,9,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,9,10,10,10,10,10,10,10,9,10,10,
10,9,10,9,9,8,9,9,10,9,10,10,10,9,10,10,11,10,11,10,10,9,10,10,11,10,11,10,10,10,
10,10,10,10,10,10,10,9,10,10,10,10,10,10,11,10,10,10,11,10,11,11,11,10,11,10,11,10,
11,10,11,10,11,10,10,10,10,10,10,9,10,10,10,10,10,10,11,10,11,10,11,10,11,11,11,10,11,11,11,
10,11,11,11,10,11,11,11,11,11,11,11,10,11,11,11,11,11,11,11,10,11,11,11,11,11,11,11,
10,11,11,11,10,11,11,11,10,11,10,11,10,10,10,10,9,10,10,10,10,11,10,11,10,11,11,11,10,11,
11,11,10,11,11,11,11,11,11,11,10,11,11,11,11,11,11,11,10,11,11,11,11,11,11,11,11,
11,11,11,11,11,11,11,10,11,11,11,11,11,11,11,11,11,11,11,11,11,11,11,10,11,11,11,11,11,
11,11,11,11,11,11,11,12,11,12,11,11,11,12,11,12,11,11,11,11,11,11,11,11,11,11,10,11,11,
11,11,11,11,11,11,11,11,12,11,12,11,11,10,11,11,12,11,12,11,11,10,11,11,11,10,11,10,10,9,10,
10,11,10,11,11,11,10,11,11,12,11,12,11,11,10,11,11,12,11,12,12,11,11,12,12,12,11,12,11,11,10,
11,11,12,11,12,12,12,11,11,12,12,11,12,11,12,11,11,11,12,11,12,11,11,11,12,11,11,11,11,11,11,10,11,
11,11,11,11,11,12,11,11,11,12,11,12,12,12,11,12,11,12,11,12,12,12,11,12,12,12,12,12,
12,12,11,12,12,12,11,12,12,12,11,12,12,12,11,12,12,12,11,12,12,12,11,12,11,12,11,
12,11,11,11,11,11,11,10,11,11,11,11,11,11,12,11,12,11,12,11,12,12,
12,11,12,12,12,11,12,12,12,11,12,12,12,12,12,12,12,11,12,12,12,12,12,12,12,11,12,12,
12,12,12,12,12,11,12,12,12,12,12,12,12,12,12,12,12,12,12,12,12,11,12,12,12,12,12,12,
12,12,12,12,12,12,12,12,12,11,12,12,12,12,12,12,12,12,12,12,12,12,12,12,
12,11,12,12,12,12,12,12,12,11,12,12,12,12,12,12,12,11,12,12,12,11,12,12,12,11,12,
11,12,11,11,11,11,10,11,11,11,11,12,11,12,11,12,12,12,11,12,12,12,11,12,12,12,12,
12,12,12,11,12,12,12,12,12,12,12,11,12,12,12,12,12,12,12,12,12,12,13,12,12,12,
12,11,12,12,12,12,13,12,12,12,12,12,12,12,12,12,12,11,12,12,12,12,12,12,12,12,12,
12,12,12,12,12,13,12,12,12,13,12,13,12,12,12,13,12,12,12,12,12,12,11,12,12,12,12,12,
12,13,12,12,12,13,12,13,12,12,12,13,12,13,12,13,12,12,12,12,12,12,12,12,12,
12,11,12,12,12,12,12,12,12,12,12,12,13,12,13,12,13,12,13,12,13,12,13,12,13,12,13,
13,13,12,13,13,13,12,13,12,13,12,13,13,13,12,13,13,13,12,13,12,13,12,12,12,13,12,
13,12,12,12,12,12,12,12,12,12,12,11,12,12,12,12,12,12,12,12,12,12,13,12,13,12,
12,12,12,12,13,12,13,13,13,12,13,13,13,12,13,12,12,11,12,12,13,12,13,13,13,12};

int main()
{
    int n;
    while(scanf("%d",&n) == 1 && n)
        printf("%d\n", ans[n-1]);
    return 0;
}

 

 可以看到最大才是13,次数不会很多。

UVa 1374 Power Calculus (IDA*或都打表)

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原文地址:http://www.cnblogs.com/dwtfukgv/p/5599275.html

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