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https://leetcode.com/problems/convert-sorted-list-to-binary-search-tree/
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* sortedListToBST(ListNode* head) { if (!head) return NULL; vector<int> tmp; tmp.push_back(0); while (head) { tmp.push_back(head->val); head = head->next; } function<TreeNode*(int, int)> dfs = [&dfs, &tmp](int lb, int ub) -> TreeNode* { if (lb > ub) return NULL; int m = (lb + ub) >> 1; auto p = new TreeNode(tmp[m]); p->left = dfs(lb, m - 1); p->right = dfs(m + 1, ub); return p; }; return dfs(1, tmp.size() - 1); } };
leetcode 109 Convert Sorted List to Binary Search Tree
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原文地址:http://www.cnblogs.com/GadyPu/p/5612453.html