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剑指offer第四十一题-拓展:和为s的连续正数序列:输入一个正数s,打印出所有和为s的连续正数序列(至少含有两个数)
1 //============================================================================ 2 // Name : JZ-C-41-Plus.cpp 3 // Author : Laughing_Lz 4 // Version : 5 // Copyright : All Right Reserved 6 // Description : 和为s的连续正数序列:输入一个正数s,打印出所有和为s的连续正数序列(至少含有两个数) 7 //============================================================================ 8 9 #include <iostream> 10 #include <stdio.h> 11 using namespace std; 12 13 void PrintContinuousSequence(int small, int big); 14 15 void FindContinuousSequence(int sum) { 16 if (sum < 3) 17 return; 18 19 int small = 1; 20 int big = 2; 21 int middle = (1 + sum) / 2; 22 int curSum = small + big; //这里curSum其实是从small到big之间所有数字的累加和 23 24 while (small < middle) { 25 if (curSum == sum) 26 PrintContinuousSequence(small, big); 27 28 while (curSum > sum && small < middle) { 29 curSum -= small; //每次更新curSum值 30 small++; 31 32 if (curSum == sum) 33 PrintContinuousSequence(small, big); 34 } 35 // while (curSum <= sum && small < middle) { //自己写的还是不如源码啊。。清晰却不简洁 36 // big++; 37 // curSum += big; 38 // if (curSum >= sum) 39 // break; 40 // } 41 big++; 42 curSum += big; //每次更新curSum值 43 } 44 } 45 46 void PrintContinuousSequence(int small, int big) { 47 for (int i = small; i <= big; ++i) 48 printf("%d ", i); 49 50 printf("\n"); 51 } 52 53 // ====================测试代码==================== 54 void Test(char* testName, int sum) { 55 if (testName != NULL) 56 printf("%s for %d begins: \n", testName, sum); 57 58 FindContinuousSequence(sum); 59 } 60 61 int main(int argc, char** argv) { 62 Test("test1", 1); 63 Test("test2", 3); 64 Test("test3", 4); 65 Test("test4", 9); 66 Test("test5", 15); 67 Test("test6", 100); 68 69 return 0; 70 }
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原文地址:http://www.cnblogs.com/Laughing-Lz/p/5615247.html