How would you print just the 10th line of a file?
For example, assume that file.txt has the following content:
Line 1 Line 2 Line 3 Line 4 Line 5 Line 6 Line 7 Line 8 Line 9 Line 10
Your script should output the tenth line, which is:
Line 10
Hint:
1. If the file contains less than 10 lines, what should you output?
2. There‘s at least three different solutions. Try to explore all possibilities.
这个题目只能用bash，以前没有太注意leetcode的show hint，今天偶然打开看了看，很有启发。
最开始我的思路是：
head -10 file.txt|tail -1
跑了五个test case后，出错了
Input: 1\n2\n3\n4\n5\n6\n7\n8\n9
Output: 9
Expected:
这个就是上面hint中提到的，当他不足10行的时候，应该输出什么
于是，改用sed，通过测试，Runtime: 16 ms。
sed -n ‘10p‘ file.txt
原文地址：http://9800561.blog.51cto.com/9790561/1792774
