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Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
#include<stdio.h> #include<string.h> #include<iostream> using namespace std; //**************************************************** //最大流模板 SAP算法 //邻接表形式 //****************************************************** const int MAXN = 100000+110;//点数的最大值 const int MAXM = 4000110;//边数的最大值 const int INF = 0x3f3f3f3f; struct Node { int from,to,next; int cap; }edge[MAXM]; int tol; int head[MAXN]; int dep[MAXN]; int gap[MAXN];//gap[x]=y :说明残留网络中dep[i]==x的个数为y int n;//n是总的点的个数,包括源点和汇点 void init() { tol=0; memset(head,-1,sizeof(head)); } void addedge(int u,int v,int w) { edge[tol].from=u; edge[tol].to=v; edge[tol].cap=w; edge[tol].next=head[u]; head[u]=tol++; edge[tol].from=v; edge[tol].to=u; edge[tol].cap=0; edge[tol].next=head[v]; head[v]=tol++; } void BFS(int start,int end) { memset(dep,-1,sizeof(dep)); memset(gap,0,sizeof(gap)); gap[0]=1; int que[MAXN]; int front,rear; front=rear=0; dep[end]=0; que[rear++]=end; while(front!=rear) { int u=que[front++]; if(front==MAXN)front=0; for(int i=head[u];i!=-1;i=edge[i].next) { int v=edge[i].to; if(dep[v]!=-1)continue; que[rear++]=v; if(rear==MAXN)rear=0; dep[v]=dep[u]+1; ++gap[dep[v]]; } } } int SAP(int start,int end) { int res=0; BFS(start,end); int cur[MAXN]; int S[MAXN]; int top=0; memcpy(cur,head,sizeof(head)); int u=start; int i; while(dep[start]<n) { if(u==end) { int temp=INF; int inser; for(i=0;i<top;i++) if(temp>edge[S[i]].cap) { temp=edge[S[i]].cap; inser=i; } for(i=0;i<top;i++) { edge[S[i]].cap-=temp; edge[S[i]^1].cap+=temp; } res+=temp; top=inser; u=edge[S[top]].from; } if(u!=end&&gap[dep[u]-1]==0)//出现断层,无增广路 break; for(i=cur[u];i!=-1;i=edge[i].next) if(edge[i].cap!=0&&dep[u]==dep[edge[i].to]+1) break; if(i!=-1) { cur[u]=i; S[top++]=i; u=edge[i].to; } else { int min=n; for(i=head[u];i!=-1;i=edge[i].next) { if(edge[i].cap==0)continue; if(min>dep[edge[i].to]) { min=dep[edge[i].to]; cur[u]=i; } } --gap[dep[u]]; dep[u]=min+1; ++gap[dep[u]]; if(u!=start)u=edge[S[--top]].from; } } return res; } int num[1025]; int bit[11]; int main() { int N,M; int v; bit[0]=1; for(int i=1;i<=10;i++) bit[i]=bit[i-1]*2; while(scanf("%d%d",&N,&M)!=EOF){ if(N==0||M==0) break; int st,ed; init(); st=0,ed=N+M+1; n=N+M+2; memset(num,0,sizeof(num)); for(int i=1;i<=N;i++){ int tmp=0; for(int j=0;j<M;j++){ //状态压缩 scanf("%d",&v); tmp+=v*bit[j]; } num[tmp]++; } for(int i=0;i<1024;i++){ if(num[i]==0) continue; addedge(i+1+M,ed,num[i]); for(int j=0;j<10;j++) if(i&bit[j]) addedge(j+1,i+1+M,INF); } for(int i=1;i<=M;i++){ scanf("%d",&v); addedge(st,i,v); } int ans=SAP(st,ed); if(ans==N) printf("YES\n"); else printf("NO\n"); } return 0; }
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原文地址:http://www.cnblogs.com/wangdongkai/p/5616624.html