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Non-unique Elements

You are given a non-empty list of integers (X). For this task, you should return a list consisting of only the non-unique elements in this list. To do so you will need to remove all unique elements (elements which are contained in a given list only once). When solving this task, do not change the order of the list. Example: [1, 2, 3, 1, 3] 1 and 3 non-unique elements and result will be [1, 3, 1, 3].

题目大义：将数组中唯一的元素清除

还是C语言的思想，直接粗暴，首先是遍历求出唯一的元素，再使用数组的remove方法

 1 def checkio(data):
 2     
 3     only = []
 4 
 5     for each in data:
 6         count = 0
 7         for other in data:
 8             if each == other:
 9                 count += 1
10 
11         if count == 1:
12             only.append(each)
13 
14     for each in only:
15         data.remove(each)
16 
17     return data

当然我们有更高级的方法list = [x for x in data if x.count > 1]，简单明了，使用了数组的另一种构造方法，使用了数组count方法

1 def checkio(data):
2     list = [x for x in data if data.count(x) > 1]
3     return list

新技能get

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Non-unique Elements

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原文地址：http://www.cnblogs.com/hzhesi/p/3891495.html