标签:des style blog class code ext
Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 5684 | Accepted: 2894 |
Description
Input
Output
Sample Input
4 6 4 3 2 2 1 1 5 3 2 1 1 400 12 50 50 50 50 50 50 25 25 25 25 25 25 0 0
Sample Output
Sums of 4: 4 3+1 2+2 2+1+1 Sums of 5: NONE Sums of 400: 50+50+50+50+50+50+25+25+25+25 50+50+50+50+50+25+25+25+25+25+25
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#include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <algorithm> using
namespace std; const
int maxn=10+5; int
a[maxn],cur[maxn]; int
ok,sum,n; inline
void DFS( int
index, int
cursum, int
cnt) { if (cursum==0) { ok=0; printf ( "%d" ,cur[0]); for ( int
i=1;i<cnt;i++) { printf ( "+%d" ,cur[i]); } printf ( "\n" ); return
; } else { for ( int
i=index;i<n;i++) { if (i==index||a[i]!=a[i-1]) //注意去重,如果当前这个数是这一层的第一个,一定要,如果不是第一个,并且和前一个相同,就不用考虑 { //因为如果与前面一个相同,就相当于当前这个串是前面的一个子串 cur[cnt]=a[i]; DFS(i+1,cursum-a[i],cnt+1); } } } return
; } int
main() { while ( scanf ( "%d%d" ,&sum,&n)!=EOF&&n!=0) { memset (cur,0, sizeof (cur)); memset (a,0, sizeof (a)); for ( int
i=0;i<n;i++) scanf ( "%d" ,&a[i]); ok=1; printf ( "Sums of %d:\n" ,sum); DFS(0,sum,0); if (ok) printf ( "NONE\n" ); } return
0; } |
标签:des style blog class code ext
原文地址:http://www.cnblogs.com/scottding/p/3712977.html