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和前两题已经关系不大了……是树的dfs,加上一个表track back
1 public int rob(TreeNode root) { 2 if(root == null) { 3 return 0; 4 } 5 Map<TreeNode, Integer> a = new HashMap<TreeNode, Integer>(); 6 Map<TreeNode, Integer> b = new HashMap<TreeNode, Integer>(); 7 return Math.max(sum(root, true, a, b), sum(root, false, a, b)); 8 } 9 10 private int sum(TreeNode root, boolean visited, Map<TreeNode, Integer> a, Map<TreeNode, Integer> b) { 11 if(root == null) { 12 return 0; 13 } 14 if (!visited && a.containsKey(root)) { 15 return a.get(root); 16 } 17 if (visited && b.containsKey(root)) { 18 return b.get(root); 19 } 20 int left = sum(root.left, false, a, b); 21 int right = sum(root.right, false, a, b); 22 if(visited) { 23 b.put(root, left + right); 24 return left + right; 25 } else { 26 int leftTrue = sum(root.left, true, a, b); 27 int rightTrue = sum(root.right, true, a, b); 28 int sum = Math.max(left + right, leftTrue + rightTrue + root.val); 29 a.put(root, sum); 30 return sum; 31 } 32 }
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原文地址:http://www.cnblogs.com/warmland/p/5626426.html