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import java.util.Stack; class Node { private char key; private Node left, right; public Node(char key) { this(key, null, null); } public Node(char key, Node left, Node right) { this.key = key; this.left = left; this.right = right; } public char getKey() { return key; } public void setKey(char key) { this.key = key; } public Node getLeft() { return left; } public void setLeft(Node left) { this.left = left; } public Node getRight() { return right; } public void setRight(Node right) { this.right = right; } } public class BinaryTree { protected Node root; public BinaryTree(Node root) { this.root = root; } public Node getRoot() { return root; } /** 构造树 */ public static Node init() { Node a = new Node(‘A‘); Node b = new Node(‘B‘, null, a); Node c = new Node(‘C‘); Node d = new Node(‘D‘, b, c); Node e = new Node(‘E‘); Node f = new Node(‘F‘, e, null); Node g = new Node(‘G‘, null, f); Node h = new Node(‘H‘, d, g); return h;// root } /** 访问节点 */ public static void visit(Node p) { System.out.print(p.getKey() + " "); } /** 递归实现前序遍历 */ protected static void preorder(Node p) { if (p != null) { visit(p); preorder(p.getLeft()); preorder(p.getRight()); } } /** 递归实现中序遍历 */ protected static void inorder(Node p) { if (p != null) { inorder(p.getLeft()); visit(p); inorder(p.getRight()); } } /** 递归实现后序遍历 */ protected static void postorder(Node p) { if (p != null) { postorder(p.getLeft()); postorder(p.getRight()); visit(p); } } //前序非递归实现 protected static void iterativePreorder(Node p) { Stack<Node> stack = new Stack<Node>(); Node node = p; while (node != null || stack.size() > 0) { while (node != null) {//压入所有的左节点,压入前访问它。左节点压入完后pop访问右节点。像这样算法时思考规律性的东西在哪。不管哪个节点都要压所节点判断右节点。 visit(node); stack.push(node); node = node.getLeft(); } if (stack.size() > 0) {// node = stack.pop(); node = node.getRight(); } } } //中序非递归实现 protected static void iterativeInorder(Node p) { Stack<Node> stack = new Stack<Node>(); Node node = p; while(node != null || stack.size() > 0) { while (node != null) { stack.push(node); node = node.getLeft(); } if (stack.size() > 0) { node = stack.pop(); visit(node); node = node.getRight(); } } } //后序非递归实现 protected static void iterativePostorder(Node p) { Node q = p; Stack<Node> stack = new Stack<Node>(); while (p != null) { // 左子树入栈 for (; p.getLeft() != null; p = p.getLeft()) stack.push(p); // 当前节点无右子或右子已经输出 while (p != null && (p.getRight() == null || p.getRight() == q)) { visit(p); q = p;// 记录上一个已输出节点 if (stack.empty()) return; p = stack.pop(); } // 处理右子 stack.push(p); p = p.getRight(); } } public static void main(String[] args) { BinaryTree tree = new BinaryTree(init()); System.out.print(" 递归前序遍历 \n"); preorder(tree.getRoot()); System.out.println(); System.out.print(" 递归中序遍历 \n"); inorder(tree.getRoot()); System.out.println(); System.out.print(" 递归后序遍历 \n"); postorder(tree.getRoot()); System.out.println(); System.out.print(" 非递归前序遍历 \n"); iterativePreorder(tree.getRoot()); System.out.println(); System.out.print(" 非递归中序遍历 \n"); iterativeInorder(tree.getRoot()); System.out.println(); System.out.print(" 非递归后序遍历 \n"); iterativePostorder(tree.getRoot()); } }
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原文地址:http://www.cnblogs.com/myseries/p/5634295.html