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Given a rotated sorted array, recover it to sorted array in-place.
What is rotated array?
[4, 5, 1, 2, 3]
-> [1, 2, 3, 4, 5]
分析:
利用公式 (A^TB^T)^T = BA
1 public class Solution { 2 /** 3 * @param nums: The rotated sorted array 4 * @return: void 5 * cnblogs.com/beiyeqingteng/ 6 */ 7 public void recoverRotatedSortedArray(ArrayList<Integer> nums) { 8 if (nums==null || nums.size()==0 || nums.size()==1) return; 9 int i = 0; 10 for (i=0; i<nums.size()-1; i++) { 11 if (nums.get(i) > nums.get(i+1)) break; 12 } 13 if (i == nums.size()-1) return; 14 reverse(nums, 0, i); 15 reverse(nums, i+1, nums.size()-1); 16 reverse(nums, 0, nums.size()-1); 17 } 18 19 public void reverse(ArrayList<Integer> nums, int l, int r) { 20 while (l < r) { 21 int temp = nums.get(l); 22 nums.set(l, nums.get(r)); 23 nums.set(r, temp); 24 l++; 25 r--; 26 } 27 } 28 }
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原文地址:http://www.cnblogs.com/beiyeqingteng/p/5634823.html