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Recover Rotated Sorted Array

时间:2016-07-02 10:25:30      阅读:219      评论:0      收藏:0      [点我收藏+]

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Given a rotated sorted array, recover it to sorted array in-place.

Clarification

What is rotated array?

  • For example, the orginal array is [1,2,3,4], The rotated array of it can be [1,2,3,4], [2,3,4,1], [3,4,1,2], [4,1,2,3]
Example

[4, 5, 1, 2, 3] -> [1, 2, 3, 4, 5]

分析:

利用公式 (A^TB^T)^T = BA

 1 public class Solution {
 2     /**
 3      * @param nums: The rotated sorted array
 4      * @return: void
 5      * cnblogs.com/beiyeqingteng/
 6      */
 7     public void recoverRotatedSortedArray(ArrayList<Integer> nums) {
 8         if (nums==null || nums.size()==0 || nums.size()==1) return;
 9         int i = 0;
10         for (i=0; i<nums.size()-1; i++) {
11             if (nums.get(i) > nums.get(i+1)) break;
12         }
13         if (i == nums.size()-1) return;
14         reverse(nums, 0, i);
15         reverse(nums, i+1, nums.size()-1);
16         reverse(nums, 0, nums.size()-1);
17     }
18     
19     public void reverse(ArrayList<Integer> nums, int l, int r) {
20         while (l < r) {
21             int temp = nums.get(l);
22             nums.set(l, nums.get(r));
23             nums.set(r, temp);
24             l++;
25             r--;
26         }
27     }
28 }

 

 

Recover Rotated Sorted Array

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原文地址:http://www.cnblogs.com/beiyeqingteng/p/5634823.html

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