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树的遍历。
#include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<string> #include<iostream> #include<algorithm> using namespace std; const int maxn=100000+10; vector<int>tree[maxn]; int n; double P,r; double sum; int sz; int num[maxn]; void dfs(int x,double price) { if(tree[x].size()==0) { sum=sum+num[x]*price; sz++; return; } for(int i=0;i<tree[x].size();i++) dfs(tree[x][i],price*(1+r/100)*1.0); } int main() { scanf("%d",&n); scanf("%lf%lf",&P,&r); for(int i=0;i<n;i++) { int ki; scanf("%d",&ki); if(ki==0) { int x; scanf("%d",&x); num[i]=x; } else { while(ki--) { int to; scanf("%d",&to); tree[i].push_back(to); } } } sum=0;sz=0; dfs(0,P); printf("%.1lf\n",sum); return 0; }
PAT (Advanced Level) 1079. Total Sales of Supply Chain (25)
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原文地址:http://www.cnblogs.com/zufezzt/p/5636188.html