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Leetcode | Container With Most Water

时间:2014-08-05 18:54:19      阅读:282      评论:0      收藏:0      [点我收藏+]

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Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

暴力超时。网上的算法,左右两指针。。。

 1 class Solution {
 2 public:
 3     int maxArea(vector<int> &height) {
 4         int i = 0, j = height.size() - 1, water, max = 0;
 5         while (i < j) {
 6             if (height[i] < height[j]) {
 7                 water = (j - i) * height[i];
 8                 i++;
 9             } else {
10                 water = (j - i) * height[j];
11                 j--;
12             }
13             if (water > max) max = water;
14         }
15         return max;
16     }
17 };

 

Leetcode | Container With Most Water,布布扣,bubuko.com

Leetcode | Container With Most Water

标签:style   blog   color   os   io   for   ar   div   

原文地址:http://www.cnblogs.com/linyx/p/3892838.html

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