标签:
Time Limit: 5000MS | Memory Limit: 65536KB | 64bit IO Format: %I64d & %I64u |
Description
For the daily milking, Farmer John‘s N cows (1 ≤ N ≤ 50,000) always line up in the same order. One day Farmer John decides to organize a game of Ultimate Frisbee with some of the cows. To keep things simple, he will take a contiguous range of cows from the milking lineup to play the game. However, for all the cows to have fun they should not differ too much in height.
Farmer John has made a list of Q (1 ≤ Q ≤ 200,000) potential groups of cows and their heights (1 ≤ height ≤ 1,000,000). For each group, he wants your help to determine the difference in height between the shortest and the tallest cow in the group.
Input
Output
Sample Input
6 3 1 7 3 4 2 5 1 5 4 6 2 2
Sample Output
6 3 0
Source
1 #include<iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include<cmath> 5 #include<algorithm> 6 #include<queue> 7 #include<cstdlib> 8 #include<iomanip> 9 #include<cassert> 10 #include<climits> 11 #define maxn 100001 12 #define F(i,j,k) for(int i=j;i<=k;i++) 13 #define M(a,b) memset(a,b,sizeof(a)) 14 #define FF(i,j,k) for(int i=j;i>=k;i--) 15 #define inf 0x7fffffff 16 #define maxm 21 17 using namespace std; 18 int read(){ 19 int x=0,f=1;char ch=getchar(); 20 while(ch<‘0‘||ch>‘9‘){if(ch==‘-‘)f=-1;ch=getchar();} 21 while(ch>=‘0‘&&ch<=‘9‘){x=x*10+ch-‘0‘;ch=getchar();} 22 return x*f; 23 } 24 int fm[maxn][maxm],fi[maxn][maxm],p[maxn]; 25 int n,q; 26 inline int init() 27 { 28 cin>>n>>q; 29 F(i,1,n){ 30 cin>>p[i]; 31 } 32 F(i,1,n){ 33 fm[i][0]=fi[i][0]=p[i]; 34 } 35 int m=floor((int)(log10((double)n)/log10((double)2))); 36 F(j,1,m)F(i,1,n){ 37 fm[i][j]=max(fm[i+(1<<(j-1))][j-1],fm[i][j-1]); 38 fi[i][j]=min(fi[i+(1<<(j-1))][j-1],fi[i][j-1]); 39 } 40 } 41 inline int stmax(int a,int b) 42 { 43 int m=floor((int)(log10((double)(b-a+1))/log10((double)2))); 44 return max(fm[a][m],fm[b-(1<<m)+1][m]); 45 } 46 inline int stmin(int a,int b) 47 { 48 int m=floor((int)(log10((double)(b-a+1))/log10((double)2))); 49 return min(fi[a][m],fi[b-(1<<m)+1][m]); 50 } 51 int main() 52 { 53 std::ios::sync_with_stdio(false);//cout<<setiosflags(ios::fixed)<<setprecision(1)<<y; 54 // freopen("data.in","r",stdin); 55 // freopen("data.out","w",stdout); 56 init();int c; 57 while(q--) 58 { 59 int a,b; 60 cin>>a>>b; 61 if(a>b) swap(a,b); 62 c=stmax(a,b)-stmin(a,b); 63 cout<<c<<endl; 64 } 65 return 0; 66 }
标签:
原文地址:http://www.cnblogs.com/SBSOI/p/5639965.html