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机器学习实战5:k-means聚类:二分k均值聚类+地理位置聚簇实例

时间:2016-07-04 23:26:24      阅读:214      评论:0      收藏:0      [点我收藏+]

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  k-均值聚类是非监督学习的一种,输入必须指定聚簇中心个数k。k均值是基于相似度的聚类,为没有标签的一簇实例分为一类。

  一 经典的k-均值聚类  

  思路:  

  1 随机创建k个质心(k必须指定,二维的很容易确定,可视化数据分布,直观确定即可);

  2 遍历数据集的每个实例,计算其到每个质心的相似度,这里也就是欧氏距离;把每个实例都分配到距离最近的质心的那一类,用一个二维数组数据结构保存,第一列是最近质心序号,第二列是距离;

  3 根据二维数组保存的数据,重新计算每个聚簇新的质心;

  4 迭代2 和 3,直到收敛,即质心不再变化;

from numpy import *

def loadDataSet(fileName):      #general function to parse tab -delimited floats
    dataMat = []                #assume last column is target value
    fr = open(fileName)
    for line in fr.readlines():
        curLine = line.strip().split(\t)
        fltLine = map(float,curLine) #map all elements to float()
        dataMat.append(fltLine)
    return dataMat

def distEclud(vecA, vecB):
    return sqrt(sum(power(vecA - vecB, 2))) #la.norm(vecA-vecB)

def randCent(dataSet, k):
    n = shape(dataSet)[1]
    centroids = mat(zeros((k,n)))#create centroid mat
    for j in range(n):#create random cluster centers, within bounds of each dimension
        minJ = min(dataSet[:,j]) 
        rangeJ = float(max(dataSet[:,j]) - minJ)
        centroids[:,j] = mat(minJ + rangeJ * random.rand(k,1))
    return centroids
    
def kMeans(dataSet, k, distMeas=distEclud, createCent=randCent):
    m = shape(dataSet)[0]
    clusterAssment = mat(zeros((m,2)))#create mat to assign data points 
                                      #to a centroid, also holds SE of each point
    centroids = createCent(dataSet, k)
    clusterChanged = True
    while clusterChanged:
        clusterChanged = False
        for i in range(m):#for each data point assign it to the closest centroid
            minDist = inf; minIndex = -1
            for j in range(k):
                distJI = distMeas(centroids[j,:],dataSet[i,:])
                if distJI < minDist:
                    minDist = distJI; minIndex = j
            if clusterAssment[i,0] != minIndex: clusterChanged = True
            clusterAssment[i,:] = minIndex,minDist**2
        print centroids
        for cent in range(k):#recalculate centroids
            ptsInClust = dataSet[nonzero(clusterAssment[:,0].A==cent)[0]]#get all the point in this cluster
            centroids[cent,:] = mean(ptsInClust, axis=0) #assign centroid to mean 
    return centroids, clusterAssment

  经典的k均值聚类有很大的缺点就是很容易收敛到局部最优,为了避免这种局部最优,我们引入了二分k-均值算法。

 

  二 二分k-均值聚类算法

  二分k-均值聚类算法是基于经典k-均值算法实现的;里面调用经典k-均值(k=2),把一个聚簇分成两个,迭代到分成k个停止;

  具体思路:

  1 把整个数据集看成一个聚簇,计算质心;并用同样的数据结构二维数组保存每个实例到质心的距离;

  2 对每一个聚簇进行2-均值聚类划分;

  3 计算划分后的误差,选择所有被划分的聚簇中总误差最小的划分保存;

  4 迭代2 和 3 直到聚簇数目达到k停止;

def biKmeans(dataSet, k, distMeas=distEclud):
    m = shape(dataSet)[0]
    clusterAssment = mat(zeros((m,2)))
    centroid0 = mean(dataSet, axis=0).tolist()[0]
    centList =[centroid0] #create a list with one centroid
    for j in range(m):#calc initial Error
        clusterAssment[j,1] = distMeas(mat(centroid0), dataSet[j,:])**2
    while (len(centList) < k):
        lowestSSE = inf
        for i in range(len(centList)):
            ptsInCurrCluster = dataSet[nonzero(clusterAssment[:,0].A==i)[0],:]#get the data points currently in cluster i
            centroidMat, splitClustAss = kMeans(ptsInCurrCluster, 2, distMeas)
            sseSplit = sum(splitClustAss[:,1])#compare the SSE to the currrent minimum
            sseNotSplit = sum(clusterAssment[nonzero(clusterAssment[:,0].A!=i)[0],1])
            print "sseSplit, and notSplit: ",sseSplit,--,sseNotSplit
            if (sseSplit + sseNotSplit) < lowestSSE:
                bestCentToSplit = i
                bestNewCents = centroidMat
                bestClustAss = splitClustAss.copy()
                lowestSSE = sseSplit + sseNotSplit
        bestClustAss[nonzero(bestClustAss[:,0].A == 1)[0],0] = len(centList) #change 1 to 3,4, or whatever
        bestClustAss[nonzero(bestClustAss[:,0].A == 0)[0],0] = bestCentToSplit
        print the bestCentToSplit is: ,bestCentToSplit
        print the len of bestClustAss is: , len(bestClustAss)
        centList[bestCentToSplit] = bestNewCents[0,:].tolist()[0]#replace a centroid with two best centroids 
        centList.append(bestNewCents[1,:].tolist()[0])
        clusterAssment[nonzero(clusterAssment[:,0].A == bestCentToSplit)[0],:]= bestClustAss#reassign new clusters, and SSE
    return mat(centList), clusterAssment

  三 地理位置聚簇实例

  地理位置的经纬度正好是二维的,可以可视化出来,所以很适合聚类算法确定质心个数k值;值得注意的是,球面计算距离,不能简单的用欧式距离,而需要用球面距离公式,见函数distSLC;

  代码的含义给定n个俱乐部地址名称,然后使用urllib包,调用yahoo地图的API返回经纬度,调用我们上面实现的k均值聚类算法,找到聚簇的中心,最后利用matplotlib工具可视化出来;

import urllib
import json
def geoGrab(stAddress, city):
    apiStem = http://where.yahooapis.com/geocode?  #create a dict and constants for the goecoder
    params = {}
    params[flags] = J#JSON return type
    params[appid] = aaa0VN6k
    params[location] = %s %s % (stAddress, city)
    url_params = urllib.urlencode(params)
    yahooApi = apiStem + url_params      #print url_params
    print yahooApi
    c=urllib.urlopen(yahooApi)
    return json.loads(c.read())

from time import sleep
def massPlaceFind(fileName):
    fw = open(places.txt, w)
    for line in open(fileName).readlines():
        line = line.strip()
        lineArr = line.split(\t)
        retDict = geoGrab(lineArr[1], lineArr[2])
        if retDict[ResultSet][Error] == 0:
            lat = float(retDict[ResultSet][Results][0][latitude])
            lng = float(retDict[ResultSet][Results][0][longitude])
            print "%s\t%f\t%f" % (lineArr[0], lat, lng)
            fw.write(%s\t%f\t%f\n % (line, lat, lng))
        else: print "error fetching"
        sleep(1)
    fw.close()
    
def distSLC(vecA, vecB):#Spherical Law of Cosines
    a = sin(vecA[0,1]*pi/180) * sin(vecB[0,1]*pi/180)
    b = cos(vecA[0,1]*pi/180) * cos(vecB[0,1]*pi/180) *                       cos(pi * (vecB[0,0]-vecA[0,0]) /180)
    return arccos(a + b)*6371.0 #pi is imported with numpy

import matplotlib
import matplotlib.pyplot as plt
def clusterClubs(numClust=5):
    datList = []
    for line in open(places.txt).readlines():
        lineArr = line.split(\t)
        datList.append([float(lineArr[4]), float(lineArr[3])])
    datMat = mat(datList)
    myCentroids, clustAssing = biKmeans(datMat, numClust, distMeas=distSLC)
    fig = plt.figure()
    rect=[0.1,0.1,0.8,0.8]
    scatterMarkers=[s, o, ^, 8, p,                     d, v, h, >, <]
    axprops = dict(xticks=[], yticks=[])
    ax0=fig.add_axes(rect, label=ax0, **axprops)
    imgP = plt.imread(Portland.png)
    ax0.imshow(imgP)
    ax1=fig.add_axes(rect, label=ax1, frameon=False)
    for i in range(numClust):
        ptsInCurrCluster = datMat[nonzero(clustAssing[:,0].A==i)[0],:]
        markerStyle = scatterMarkers[i % len(scatterMarkers)]
        ax1.scatter(ptsInCurrCluster[:,0].flatten().A[0], ptsInCurrCluster[:,1].flatten().A[0], marker=markerStyle, s=90)
    ax1.scatter(myCentroids[:,0].flatten().A[0], myCentroids[:,1].flatten().A[0], marker=+, s=300)
    plt.show()

 

  四 总结

  优点:易实现;

  缺点:可能收敛到局部最小值,在大数据集上收敛较慢;

  适用数据类型:数值型

机器学习实战5:k-means聚类:二分k均值聚类+地理位置聚簇实例

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原文地址:http://www.cnblogs.com/rongyux/p/5641825.html

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