【递推与递归】极值问题

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <climits>
#include <cstring>
#include <string>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <vector>
#include <list>
#include <ext/rope>
#define rep(i,m,n) for(i=m;i<=n;i++)
#define rsp(it,s) for(set<int>::iterator it=s.begin();it!=s.end();it++)
#define vi vector<int>
#define pii pair<int,int>
#define mod 1000000007
#define inf 0x3f3f3f3f
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define ll long long
#define pi acos(-1.0)
const int maxn=1e6+10;
const int dis[4][2]={{0,1},{-1,0},{0,-1},{1,0}};
using namespace std;
using namespace __gnu_cxx;
ll gcd(ll p,ll q){return q==0?p:gcd(q,p%q);}
ll qpow(ll p,ll q){ll f=1;while(q){if(q&1)f=f*p;p=p*p;q>>=1;}return f;}
int n,m,f[40]={1,1};
int main()
{
    int i,j,k,t;
    rep(i,2,39)f[i]=f[i-1]+f[i-2];
    scanf("%d",&k);
    j=lower_bound(f,f+40,k)-f;
    if(j==0)printf("m=%d n=%d\n",f[j],f[j+1]);
    else if(f[j]>k)printf("m=%d n=%d\n",f[j-2],f[j-1]);
    else printf("m=%d n=%d\n",f[j-1],f[j]);
    //system ("pause");
    return 0;
}