码迷,mamicode.com
首页 > 其他好文 > 详细

Minimum Path Sum

时间:2016-07-08 06:47:20      阅读:116      评论:0      收藏:0      [点我收藏+]

标签:

Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

You can only move either down or right at any point in time.

 1 public class Solution {
 2     /**
 3      * @param grid: a list of lists of integers.
 4      * @return: An integer, minimizes the sum of all numbers along its path
 5      */
 6     public int minPathSum(int[][] grid) {
 7         if (grid == null) return 0;
 8         
 9         // initialize the first row
10         int [][] min = new int[grid.length][grid[0].length];
11         
12         min[0][0] = grid[0][0];
13         
14         for (int i = 1; i < grid[0].length; i++) {
15             min[0][i] = min[0][i - 1] + grid[0][i];
16         }
17         
18         for (int i = 1; i < grid.length; i++) {
19             min[i][0] = min[i - 1][0] + grid[i][0];
20         }
21         
22         for (int i = 1; i < grid.length; i++) {
23             for (int j = 1; j < grid[0].length; j++) {
24                 min[i][j] = (int)Math.min(min[i - 1][j], min[i][j - 1]) + grid[i][j];
25             }
26         }
27         
28         return min[grid.length - 1][grid[0].length - 1];
29     }
30 }

 

Minimum Path Sum

标签:

原文地址:http://www.cnblogs.com/beiyeqingteng/p/5652094.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!